T.1 SL/HL Concept 5 of 9

Fundamental & Derived Units in Physics

Part of T.1 Tools of Physics · Unit T — IB Physics 2023

5 Lesson 5 of 9 · T.1 Tools of Physics
Fundamental & Derived Units in Physics
Every physical quantity is a number times a unit; the SI system builds every unit from a small set of base (fundamental) units, so any derived unit — the joule, the pascal, the volt — can be written in base units and checked.

🎯 Hook – the $327 million unit mistake

In 1999, NASA's Mars Climate Orbiter burned up in the Martian atmosphere because one engineering team's software reported thruster impulse in pound-force seconds while the navigation software expected newton seconds. No equation was wrong — the units were. A coherent system of units isn't bureaucratic fussiness; it's what stops a $327 million spacecraft from being lost to a label.

💡 Diagnostic question — why is the newton defined as exactly \(1\ \text{kg m s}^{-2}\) and not, say, \(2\ \text{kg m s}^{-2}\)? SI is built to be coherent: combining base units through an equation (F = ma) always gives the derived unit with a factor of exactly 1, so no hidden conversion constants creep into physics equations.

🧱 SI base quantities and units

Base quantityUnitSymbol
Masskilogramkg
Lengthmetrem
Timeseconds
Electric currentampereA
Thermodynamic temperaturekelvinK
Amount of substancemolemol

Derived units are products or quotients of base units, many with special names built from defining equations:

QuantityDefining equationUnitBase units
ForceF = manewton, Nkg m s⁻²
EnergyW = Fsjoule, Jkg m² s⁻²
PowerP = W/twatt, Wkg m² s⁻³
Pressurep = F/Apascal, Pakg m⁻¹ s⁻²
ChargeQ = Itcoulomb, CA s
Potential differenceV = W/Qvolt, Vkg m² s⁻³ A⁻¹
ResistanceR = V/Iohm, Ωkg m² s⁻³ A⁻²

🔢 Prefixes, conversions and IB notation

P 10¹⁵T 10¹²G 10⁹M 10⁶k 10³ f 10⁻¹⁵p 10⁻¹²n 10⁻⁹μ 10⁻⁶m 10⁻³
Fig 1 — the SI prefix ladder from femto to peta, as given in the data booklet.

Converting units: speed km h⁻¹ → m s⁻¹ divide by 3.6; area/volume squares or cubes the prefix (\(1\ \text{cm}^2=(10^{-2}\,\text{m})^2=10^{-4}\,\text{m}^2\); \(1\ \text{cm}^3=10^{-6}\,\text{m}^3\)); density \(1\ \text{g cm}^{-3}=1000\ \text{kg m}^{-3}\); temperature \(T(\text{K})=\theta(°\text{C})+273\) (a change of 1 K equals a change of 1 °C); energy \(1\ \text{eV}=1.60\times10^{-19}\ \text{J}\), \(1\ \text{kWh}=3.6\times10^{6}\ \text{J}\).

Accepted non-SI units in IB physics: eV, u (atomic mass unit), kWh, light year, parsec, AU, °C, minute/hour/day/year, degree (angle).

IB notation: use negative indices (m s⁻¹, not m/s); a space separates number and unit and separates unit symbols (9.81 m s⁻²); symbols are case-sensitive (mW ≠ MW); no plurals, no full stops (5 kg, not 5 kgs); table headings and graph axes use quantity/unit, e.g. "v / m s⁻¹".

🌐 Deeper notes — the 2019 redefinition and dimensionless quantities

Since 20 May 2019, all seven SI base units are defined by fixing the numerical values of constants of nature — the caesium hyperfine frequency (second), the speed of light (metre), the Planck constant (kilogram), the elementary charge (ampere). The kilogram is no longer defined by a metal cylinder kept in Paris, which could be damaged or drift in mass over time; a constant of nature is reproducible anywhere.

Dimensionless quantities — ratios of the same kind of quantity have no unit: strain, refractive index, efficiency, coefficient of friction. Angles in radians are formally dimensionless (m/m) but the "rad" label is kept for clarity.

Coherence: combining base units in an equation gives a derived unit with a factor of exactly 1 (\(1\ \text{N}=1\ \text{kg}\times1\ \text{m s}^{-2}\)); mixing units (g with m, say) breaks this and gives a wrong number by a power of ten.

📊 Graph mastery — temperature and prefix scales

Graph typeAxes (X, Y)ShapeWhat to read
Temperature in K vs °C°C · KStraight line, gradient 1Intercept at 273 K (0 °C)
Log-scale prefix chartpower of ten · example objectEvenly spaced decades, femto to petaWhere a given quantity sits among the prefixes
θ / °CT / K 273 K at 0 °C
Fig 2 — T(K) = θ(°C) + 273: a straight line of gradient 1.

✍️ Worked example 1 — deriving units from an equation

1
Joule: \(W=Fs \to \text{N}\times\text{m} = (\text{kg m s}^{-2})(\text{m}) = \mathbf{kg\ m^2\ s^{-2}}\).
2
Spring constant: \(k=F/x \to \text{N m}^{-1} = (\text{kg m s}^{-2})/\text{m} = \mathbf{kg\ s^{-2}}\).
3
Gravitational constant: from \(F=Gm_1m_2/r^2\), \(G=Fr^2/(m_1m_2) \to (\text{kg m s}^{-2})(\text{m}^2)/\text{kg}^2 = \mathbf{m^3\ kg^{-1}\ s^{-2}}\).

✍️ Worked example 2 — conversions in practice

1
Density: \(2.7\ \text{g cm}^{-3} = \dfrac{2.7\times10^{-3}\ \text{kg}}{10^{-6}\ \text{m}^3} = \mathbf{2700\ kg\,m^{-3}}\).
2
Energy: \(1.2\ \text{kWh}=1.2\times3.6\times10^{6}=\mathbf{4.3\times10^{6}\ J}\); \(5.0\ \text{MeV}=5.0\times10^6\times1.60\times10^{-19}=\mathbf{8.0\times10^{-13}\ J}\).
3
Comparing pressures: atmospheric 101 kPa; Mariana Trench ≈ 110 MPa. Ratio \(=1.1\times10^{8}/1.01\times10^{5}\approx1.1\times10^{3}\) → about three orders of magnitude greater.

🌍 Real-world: unit mistakes cost money

The Mars Climate Orbiter's loss is the textbook case, but unit slips happen constantly in engineering, medicine (dosage units) and finance. A written "/ unit" column on every table and graph axis is not a formality — it is the single habit that catches this class of error before it becomes expensive.

✓ Examiner tip: convert every quantity to SI base units before substituting into an equation; a missing or mismatched unit on a final answer often costs the mark even if the number is right.

🚀 Going further — why fix constants, not artefacts?

A physical artefact (like the old kilogram cylinder) can be damaged, contaminated, or simply drift in mass with handling over decades — and only one copy exists to compare against. Defining units from constants of nature (the Planck constant, the speed of light) gives a definition any suitably equipped lab anywhere can realise independently, with no risk of loss or drift.

Challenge: strain (extension/original length) has no unit. What does this tell you about combining it in an equation like stress = (Young modulus) × strain? Since strain is dimensionless, the Young modulus must carry the same units as stress (Pa) — nothing is "hidden" in a dimensionless factor.

📋 Quick practice — answers in italics

(a) Convert 108 km h⁻¹ to m s⁻¹. 30 m s⁻¹.

(b) Convert 450 nm to m. 4.50×10⁻⁷ m.

(c) Convert 37 °C to kelvin. 310 K.

(d) A 60 W lamp runs for 3.0 h — find the energy used in J and kWh. 6.48×10⁵ J = 0.18 kWh.

(e) Identify the errors in "the car's speed was 20 M/S and its mass 1.2 Kgs." "M" should be lowercase "m" (M means mega); units take no plural "s"; the slash form is non-standard IB style (m s⁻¹, kg).

⚠️ Trap corner – common mistakes

MisconceptionCorrect view
The gram is the SI base unit of massThe kilogram is the base unit — the only base unit that already carries a prefix
Prefixes apply linearly to squared/cubed units\(\text{cm}^2=10^{-4}\ \text{m}^2\), not \(10^{-2}\) — the prefix is squared (or cubed) too
mW and MW are easy to mix upm = milli (10⁻³), M = mega (10⁶) — a million-fold difference; read case carefully
Kelvin takes a degree sign300 K, never "300 °K" — kelvin is an absolute scale with no degree symbol
km h⁻¹ → m s⁻¹ by multiplying by 3.6Divide by 3.6 to convert km h⁻¹ to m s⁻¹ (multiply to go the other way)
kWh and kW measure the same thingkWh is energy; kW is power — don't confuse a rate with a total
⚠️ Most common slip: forgetting that charge is a derived quantity (C = A s) while current is the base quantity — many students assume charge is more fundamental because it feels more basic physically.
6 base units: kg, m, s, A, K, mol N = kg m s⁻² J = kg m² s⁻² W = kg m² s⁻³ Pa = kg m⁻¹ s⁻² cm² = 10⁻⁴ m² km h⁻¹ ÷ 3.6 = m s⁻¹ T(K) = θ(°C) + 273
Practice check — multiple choice
1. Which is an SI base unit?
A Newton
B Ampere
C Volt
D Joule
2. The joule expressed in SI base units is:
A kg m s⁻²
B kg m s⁻¹
C kg m² s⁻³
D kg m² s⁻²
3. 72 km h⁻¹ in m s⁻¹ is:
A 7.2
B 259
C 20
D 2.0
4. 1 cm² is equal to:
A 1×10⁻⁴ m²
B 1×10⁻² m²
C 1×10⁻⁶ m²
D 1×10² m²
5. Which is NOT an SI base quantity?
A Mass
B Temperature
C Amount of substance
D Electric charge
6. 5.0 μA is equal to:
A 5.0×10⁻³ A
B 5.0×10⁻⁶ A
C 5.0×10⁻⁹ A
D 5.0×10⁶ A
7. The pascal in SI base units is:
A kg m s⁻²
B kg m² s⁻²
C kg m⁻¹ s⁻²
D kg m⁻² s⁻²
8. A density of 2.7 g cm⁻³ in SI units is:
A 2700 kg m⁻³
B 2.7 kg m⁻³
C 270 kg m⁻³
D 0.0027 kg m⁻³
9. Which quantity is dimensionless?
A Frequency
B Strain rate
C Density
D Refractive index
10. The watt in SI base units is:
A kg m² s⁻²
B kg m² s⁻³
C kg m s⁻³
D kg m² s⁻¹
Practice check — fill in the blanks

Complete the statements:

The SI base unit of mass is the , not the gram. When converting cm² to m², the prefix must be too. Temperature on the absolute scale is measured in with no degree symbol. A quantity with no unit, such as strain or refractive index, is said to be .
Exam‑style questions
Exam question · Derive / Determine / State
Q1. (a) Derive the unit of pressure in terms of SI base units. (b) Atmospheric pressure at sea level is 101 kPa; at the bottom of the Mariana Trench it is about 110 MPa. Determine how many orders of magnitude greater the trench pressure is. (c) State one non-SI unit of pressure you may meet. [5 marks]
✓ (a) \(p=F/A \to (\text{kg m s}^{-2})/\text{m}^2 = \mathbf{kg\ m^{-1}\ s^{-2}}\).
✓ (b) \(1.1\times10^8/1.01\times10^5\approx1.1\times10^3\) → about 3 orders of magnitude.
✓ (c) The atmosphere (atm), the bar, or mmHg.
Exam question · Determine / Calculate
Q2. The drag force on a car is \(F=kv^2\). (a) Determine the SI base units of k. (b) At 30 m s⁻¹ the drag force is 540 N — calculate k. (c) Calculate the drag force at 90 km h⁻¹. [5 marks]
✓ (a) \(k=F/v^2 \to (\text{kg m s}^{-2})/(\text{m}^2\text{s}^{-2}) = \mathbf{kg\ m^{-1}}\).
✓ (b) \(k=540/30^2=\mathbf{0.60\ kg\,m^{-1}}\).
✓ (c) \(90\ \text{km h}^{-1}=25\ \text{m s}^{-1}\); \(F=0.60\times25^2=\mathbf{375\ N}\).
Exam question · Calculate
Q3. An electric kettle rated 2.2 kW heats 1.5 kg of water from 18 °C to 100 °C (specific heat capacity 4.18 kJ kg⁻¹ K⁻¹). (a) Calculate the energy needed, in J and in kWh. (b) Calculate the minimum time taken, in minutes. [5 marks]
✓ (a) \(E=mc\Delta T=1.5\times4180\times82\approx\mathbf{5.1\times10^{5}\ J}\) \((\approx0.14\ \text{kWh})\).
✓ (b) \(t=E/P=5.14\times10^{5}/2200\approx234\ \text{s} \approx\mathbf{3.9\ min}\).
Exam question · Paper 1B practical skills — identifying a metal by density
Q4. A metal cylinder: mass \(m=42.6\pm0.1\) g; diameter \(d=25.0\pm0.1\) mm; height \(h=32.0\pm0.1\) mm. (a) Convert all measurements to SI base units. (b) Calculate the volume and density in SI units. (c) Calculate the percentage uncertainty in each measurement and hence the absolute uncertainty in the density. (d) Aluminium has density 2700 kg m⁻³ and zinc 7140 kg m⁻³ — deduce which metal it is. (e) Suggest how to reduce the largest source of uncertainty. [10 marks]
✓ (a) \(m=0.0426\) kg, \(d=0.0250\) m, \(h=0.0320\) m.
✓ (b) \(V=\pi r^2h=\pi(0.0125)^2(0.0320)=1.57\times10^{-5}\ \text{m}^3\); density \(=0.0426/1.57\times10^{-5}\approx\mathbf{2710\ kg\,m^{-3}}\).
✓ (c) %unc: mass 0.24%, diameter 0.4% (doubled to 0.8% for r²), height 0.31% — total ≈ 1.3%, so absolute uncertainty ≈ ±35 kg m⁻³.
✓ (d) 2710 ± 35 kg m⁻³ agrees with aluminium (2700 kg m⁻³) well within uncertainty, and is far from zinc.
✓ (e) The diameter dominates (doubled for r²) — use a micrometer instead of a vernier caliper, or average several measurements at different points.
Exam question · Explain
Q5. Explain why a coherent system of units (SI) makes physics calculations safer, using the Mars Climate Orbiter as an example. [2 marks]
✓ A coherent system combines base units with a factor of exactly 1, so if every quantity is in SI units, no hidden conversion constant can be forgotten.
✓ The Mars Climate Orbiter was lost because one software team used pound-force seconds and another expected newton seconds for the same impulse value — a non-SI/SI mismatch that coherent, consistent SI units would have prevented.
Exam question · Explain
Q6. Since 2019, SI units are defined by fixing constants of nature. Explain why this is better than defining the kilogram with a physical object. [2 marks]
✓ A physical artefact can be damaged, contaminated or drift slightly in mass with handling, and only one original copy exists to calibrate against.
✓ A constant of nature (e.g. the Planck constant) is the same everywhere and at all times, so any sufficiently equipped laboratory can realise the unit independently, with no risk of loss or drift.
Exam question · Discuss
Q7. Explain why electric charge is a derived quantity but current is a base quantity in SI, and whether the choice is fundamental or conventional. [2 marks]
✓ Current (A) was historically easier to realise and measure precisely (e.g. via the force between current-carrying wires), so SI chose it as the base quantity, with charge defined from it as \(Q=It\).
✓ Either could, in principle, have been chosen as fundamental — the choice is a practical convention for reproducible measurement, not a deep physical necessity.
Exam question · Discuss
Q8. Physicists often use non-SI units (eV, u, ly). Discuss the advantages and risks. [2 marks]
✓ Advantage: they make numbers at atomic or astronomical scales convenient to write and compare, avoiding extreme powers of ten in everyday calculation.
✓ Risk: forgetting to convert back to SI before combining with SI-based equations gives an answer wrong by a large, easily unnoticed factor.
Exam question · Explain
Q9. Explain why the prefix must be cubed when converting cm³ to m³, and give an example where forgetting this gives a large error. [2 marks]
✓ A volume is a length cubed, so the conversion factor on the length (10⁻² for cm→m) must also be cubed: \(1\ \text{cm}^3=(10^{-2}\,\text{m})^3=10^{-6}\,\text{m}^3\).
✓ Example: treating 100 cm³ as \(100\times10^{-2}=1\ \text{m}^3\) instead of the correct \(100\times10^{-6}=10^{-4}\ \text{m}^3\) is wrong by a factor of 10⁴.
Score: 0 pts