C.1 SL/HL Concept 5 of 5

Damping and Resonance

Part of C.1 Simple Harmonic Motion · Unit C — IB Physics 2023

5 Lesson 5 of 5 · C.1 Simple Harmonic Motion
Damping and Resonance
In practice every oscillator stops. This lesson covers the resistive forces that drain energy from an oscillating system, the three degrees of damping and their graphs, and what damping does to the resonance curve.

🎯 Hook – the swing that never keeps going

In practice, all oscillators eventually stop oscillating. Their amplitudes may decrease rapidly or gradually. This happens due to resistive forces, such as friction or air resistance, which act in the opposite direction to the motion of an oscillator. Resistive forces acting on an oscillating simple harmonic system cause damping, and the resulting motion is called damped oscillations. Damping continues until the oscillator comes to rest at the equilibrium position.

Mass on a spring oscillating, with a resistive force arrow acting in the opposite direction to the motion arrow, and the amplitude decaying to zero
Fig 1 — Damping on a mass on a spring is caused by a resistive force (\(F_{\text{R}}\)) acting in the opposite direction to the motion (blue arrow). This continues until the amplitude of the oscillations reaches zero.
💡 Diagnostic question (think – then read on) — A child on a swing loses half of their amplitude over a minute. Does each swing now take less time? No. A key feature of simple harmonic motion is that the frequency of damped oscillations does not change as the amplitude decreases. The child can oscillate back and forth once every second, and the time remains the same regardless of the amplitude.

📐 Defining damping

Damping is defined as:

📖 Damping — The reduction in energy and amplitude of oscillations due to resistive forces on the oscillating system.

Two consequences follow, and examiners test both. First, the energy of the system falls, so the amplitude falls. Second, the frequency is unchanged: successive peaks and troughs stay equally spaced in time even as they shrink.

Damped oscillation — amplitude decays, period does not $$A(t) = A_0\,e^{-\lambda t}$$ $$T = \text{constant}$$
⚠️ Make sure not to confuse resistive force and restoring force. Resistive force is what opposes the motion of the oscillator and causes damping. Restoring force is what brings the oscillator back to the equilibrium position.

📉 Light damping

There are three degrees of damping, depending on how quickly the amplitude of the oscillations decreases: light damping, critical damping and heavy damping.

When oscillations are lightly damped, the amplitude does not decrease linearly — it decays exponentially with time. When a lightly damped oscillator is displaced from the equilibrium, it will oscillate with gradually decreasing amplitude. For example, a swinging pendulum decreases in amplitude until it comes to a stop. A graph for a lightly damped system consists of oscillations decreasing exponentially.

Key features of a displacement–time graph for a lightly damped system: there are many oscillations represented by a sine or cosine curve with gradually decreasing amplitude over time; this is shown by the height of the curve decreasing in both the positive and negative displacement values; the amplitude decreases exponentially; the frequency of the oscillations remains constant, which means the time period of oscillations must stay the same, and each peak and trough are equally spaced.

Displacement against time graph for a lightly damped oscillator: many equally spaced oscillations inside an exponentially decaying envelope
Fig 2 — Light damping. Read off the equal spacing of the peaks (constant period) and the exponential envelope on both the positive and negative sides.

🚗 Critical damping

When a critically damped oscillator is displaced from the equilibrium, it will return to rest at its equilibrium position in the shortest possible time without oscillating. For example, car suspension systems prevent the car from oscillating after travelling over a bump in the road. The graph for a critically damped system shows no oscillations and the displacement returns to zero in the quickest possible time.

Key features of a displacement–time graph for a critically damped system: this system does not oscillate, meaning the displacement falls to 0 straight away; the graph has a fast decreasing gradient when the oscillator is first displaced until it reaches the x-axis; when the oscillator reaches the equilibrium position (\(x = 0\)), the graph is a horizontal line at \(x = 0\) for the remaining time.

Displacement against time graph for a critically damped system: a fast smooth fall to zero with no overshoot, then a horizontal line along the time axis
Fig 3 — Critical damping. No oscillation, a fast decreasing gradient to the x-axis, then a horizontal line at \(x = 0\).

🚪 Heavy damping

When a heavily damped oscillator is displaced from its equilibrium position, it will take a long time to return to its equilibrium position without oscillating. The system returns to equilibrium more slowly than the critical damping case. For example, door dampers prevent doors from slamming shut. A heavy damping curve has no oscillations, and the displacement returns to zero after a long period of time.

Key features of a displacement–time graph for a heavily damped system: there are no oscillations, which means the displacement does not pass 0; the graph has a slow decreasing gradient from when the oscillator is first displaced until it reaches the x-axis; the oscillator reaches the equilibrium position (\(x = 0\)) after a long period of time, after which the graph remains a horizontal line for the remaining time.

Displacement against time graph for a heavily damped system: a slow decreasing gradient reaching zero only after a long time, with no oscillation
Fig 4 — Heavy damping. The gradient is slow throughout and the displacement never passes 0.
light: oscillates, exponential decay critical: fastest, no oscillation heavy: slow, no oscillation

🔊 Effects of damping — the resonance curve

The effects of damping can be seen on a resonance curve. This is a graph of driving frequency \(f\) against amplitude \(A\) of oscillations. The graph peaks at the natural frequency \(f_0\) of the oscillator.

It has the following key features: when \(f < f_0\), the amplitude of oscillations increases; at the peak, where \(f = f_0\), the amplitude is at its maximum — this is resonance; when \(f > f_0\), the amplitude of oscillations starts to decrease. The maximum amplitude of the oscillations occurs when the driving frequency is equal to the natural frequency of the oscillator.

Condition for resonance $$f = f_0$$

Damping reduces the amplitude of resonance vibrations. The height and shape of the resonance curve will therefore change slightly depending on the degree of damping. Note: the natural frequency \(f_0\) of the oscillator will remain the same.

As the degree of damping is increased, the resonance graph is altered in the following ways: the amplitude of resonance vibrations decreases, meaning the peak of the curve lowers; the resonance peak broadens; the resonance peak moves slightly to the left of the natural frequency when heavily damped. Therefore, damping reduces the sharpness of the resonance and the amplitude of oscillations at the resonant frequency.

💡 The resonant frequency — the frequency of vibrations of the oscillator — can change with damping. The natural frequency of an oscillator is the frequency it naturally or normally oscillates at when it is not damped. Therefore, damping does not affect the natural frequency.

📈 Graphs every examiner uses

Graph typeAxes (X, Y)ShapeWhat to read
Light dampingtime \(t\), displacement \(x\)Sine/cosine curve with exponentially decreasing amplitude, symmetric about \(x = 0\)Constant period (equally spaced peaks and troughs); amplitude decaying exponentially in both directions
Critical dampingtime \(t\), displacement \(x\)No oscillation; fast decreasing gradient to the x-axis, then horizontal at \(x = 0\)Shortest possible time to equilibrium with no overshoot
Heavy dampingtime \(t\), displacement \(x\)No oscillation; slow decreasing gradient, reaching \(x = 0\) after a long timeDisplacement never passes 0; slower return than critical damping
Resonance curvedriving frequency \(f\), amplitude \(A\)Rises for \(f < f_0\), peaks at \(f = f_0\), falls for \(f > f_0\)Position of the peak (\(f_0\)); peak height and sharpness give the degree of damping
Resonance curve of amplitude against driving frequency, rising to a peak at the natural frequency f0 and falling after it
Fig 5 — A resonance curve. The peak sits at the natural frequency \(f_0\), where the amplitude is maximum.
Family of three resonance curves for increasing damping, each lower and broader, with the peak shifting slightly left of f0
Fig 6 — As damping is increased, the resonance peak lowers, the curve broadens and moves slightly to the left.

✍️ Worked example – the mechanical weighing scale

A mechanical weighing scale consists of a needle which moves to a position on a numerical scale depending on the weight applied. Sometimes the needle moves to the equilibrium position after oscillating slightly, making it difficult to read the number on the scale to which it is pointing. Suggest, with a reason, whether light, critical or heavy damping should be applied to the mechanical weighing scale to read the scale more easily.

1
Identify: this is a damping-selection question. The needle is currently lightly damped — it oscillates before settling. We must choose the degree of damping that makes the reading easiest.
2
Data (requirements): ideally, the needle should not oscillate before settling — this means the scale should have either critical or heavy damping. Since the scale is read straight away after a weight is applied, ideally, the needle should settle as quickly as possible.
3
Compare the two candidates: heavy damping would mean the needle will take some time to settle on the scale. Critical damping returns the needle to rest at equilibrium in the shortest possible time without oscillating.
4
Answer: therefore, critical damping should be applied to the weighing scale so the needle can settle as quickly as possible to read from the scale.
Mechanical weighing scale dial with a needle, shown lightly damped oscillating past the reading and critically damped settling straight onto it
Fig 7 — Geometry for the worked example: the lightly damped needle overshoots the reading; the critically damped needle settles straight onto it.

🔧 Real-world: suspension, doors and dials

Engineers choose the degree of damping to suit the job. Car suspension systems are critically damped so the car does not oscillate after travelling over a bump in the road. Door dampers are heavily damped to prevent doors from slamming shut. A weighing-scale needle is critically damped so it settles quickly enough to read.

✓ Examiner tip: when asked to justify a choice of damping, always give both halves of the mark — no oscillation and the time taken to settle.

🚀 HL Extension – sharpness of resonance

The sharpness of a resonance peak is described by the quality factor, the ratio of the resonant frequency to the width of the peak. Light damping gives a tall, narrow peak and a high \(Q\); heavy damping gives a low, broad peak and a low \(Q\).
Challenge: two identical pendulums are driven at a range of frequencies, one in air and one in water. Which has the taller, narrower resonance peak, and does its peak sit at the same frequency? (Answer: the one in air — less damping, so a taller and sharper peak; the natural frequency \(f_0\) is unchanged, but the heavily damped pendulum in water peaks slightly to the left of \(f_0\).)

⚠️ Trap corner – common mistakes

MisconceptionCorrect view
Damping lengthens \(T\)Damping does not slow the oscillation down: the frequency of damped oscillations does not change as the amplitude decreases; each peak and trough stay equally spaced
Resistive = restoringThey are different forces. Resistive force opposes the motion of the oscillator and causes damping; restoring force brings the oscillator back to the equilibrium position
Amplitude falls linearlyFor light damping, The amplitude does not decrease linearly — it decays exponentially with time
Heavy stops it fastestHeavy damping is not the fastest: Critical damping returns the oscillator to rest at equilibrium in the shortest possible time; heavy damping is slower than critical
Damping shifts \(f_0\)Damping does not affect the natural frequency; \(f_0\) stays the same, though the resonance peak moves slightly to the left when heavily damped
⚠️ Most common slip: writing that the amplitude at resonance is maximum "when damping is zero" instead of when the driving frequency equals the natural frequency. An exam question can include any damping scenario, so make sure you can interpret the amplitude–frequency graph depending on the type of oscillation.
damping = energy + amplitude loss frequency unchanged by damping light · critical · heavy resonance at f = f₀ more damping → lower, broader peak peak shifts left when heavy
Practice check — multiple choice
1. A pendulum oscillating in air loses amplitude over time. What happens to the time period of its oscillations?
A It increases as the amplitude falls
B It decreases as the amplitude falls
C It stays the same
D It falls to zero when the oscillator stops
2. Which displacement–time graph belongs to a critically damped system?
A Oscillations with an exponentially decaying amplitude
B A fast decreasing gradient to the x-axis, then a horizontal line at \(x = 0\)
C A slow decreasing gradient reaching \(x = 0\) only after a long time
D A straight line of constant negative gradient
3. A resonance curve is plotted for an oscillator, and then the experiment is repeated with more damping. Compared with the first curve, the second curve is:
A Taller and narrower, peaking at the same frequency
B The same height, but shifted to a higher frequency
C Lower and narrower, peaking well above \(f_0\)
D Lower and broader, with the peak slightly to the left of \(f_0\)
4. Which force is responsible for damping?
A The restoring force, which brings the oscillator back to equilibrium
B The resistive force, which acts in the opposite direction to the motion
C The weight of the oscillating mass
D The driving force applied by the oscillator's driver
5. A door damper is fitted so the door does not slam. Which degree of damping does it use, and why?
A Light — so the door swings back and forth a few times first
B Critical — so the door reaches the frame in the shortest possible time
C Heavy — so the door takes a long time to reach the frame, without oscillating
D None — the door is undamped
Practice check — fill in the blanks

Complete the statements:

Damping is the reduction in energy and of oscillations due to forces. In a lightly damped system the amplitude decays with time, while the frequency stays . A damped system returns to equilibrium in the shortest possible time without oscillating. A resonance curve peaks at the frequency, and increasing the damping makes that peak lower and .
Exam‑style questions
Exam question · State / Explain
(a) State what is meant by damping. [2 marks]
(b) A child on a swing oscillates back and forth once every second. Explain what happens to the amplitude and to the time period of the oscillations as the swing is damped. [2 marks]
(a) ✓ The reduction in energy and amplitude of oscillations ✓ due to resistive forces on the oscillating system.

(b) ✓ The amplitude decreases over time, because resistive forces act in the opposite direction to the motion and remove energy, until the oscillator comes to rest at the equilibrium position. ✓ The time period is unchanged — the frequency of damped oscillations does not change as the amplitude decreases, so the swing still takes one second regardless of the amplitude.
Exam question · Sketch
Three identical oscillators are released from the same initial displacement, one lightly damped, one critically damped and one heavily damped. Sketch, on the same displacement–time axes, the curve for each, and label the key feature of each. [5 marks]
✓ All three start at the same positive displacement.
✓ Light damping: many oscillations, a sine or cosine curve with gradually decreasing amplitude, decaying exponentially in both the positive and negative displacement values, with each peak and trough equally spaced (constant period).
✓ Critical damping: no oscillation; the displacement falls to 0 straight away with a fast decreasing gradient, then a horizontal line at \(x = 0\).
✓ Heavy damping: no oscillation; a slow decreasing gradient reaching \(x = 0\) only after a long period of time, then horizontal.
✓ The heavily damped curve reaches \(x = 0\) later than the critically damped curve, and only the lightly damped curve passes below \(x = 0\).
Exam question · Discuss
An oscillator is driven over a range of frequencies and the amplitude of oscillation is recorded. (a) Sketch the resonance curve and label the natural frequency \(f_0\). [2 marks]
(b) Discuss how the curve changes when the degree of damping is increased. [3 marks]
(a) ✓ Axes: driving frequency \(f\) on the horizontal, amplitude \(A\) on the vertical; the amplitude increases for \(f < f_0\) and decreases for \(f > f_0\). ✓ The peak, where the amplitude is at its maximum, is at \(f = f_0\) — this is resonance.

(b) ✓ The amplitude of resonance vibrations decreases, so the peak of the curve lowers. ✓ The resonance peak broadens. ✓ The peak moves slightly to the left of the natural frequency when heavily damped; the natural frequency \(f_0\) itself is unchanged, so damping reduces the sharpness of the resonance and the amplitude at the resonant frequency.
Exam question · Suggest
A mechanical weighing scale consists of a needle which moves to a position on a numerical scale depending on the weight applied. Sometimes the needle moves to the equilibrium position after oscillating slightly, making it difficult to read the number on the scale to which it is pointing. Suggest, with a reason, whether light, critical or heavy damping should be applied to the mechanical weighing scale to read the scale more easily. [3 marks]
✓ Ideally, the needle should not oscillate before settling — this means the scale should have either critical or heavy damping.
✓ Since the scale is read straight away after a weight is applied, ideally the needle should settle as quickly as possible; heavy damping would mean the needle will take some time to settle on the scale.
✓ Therefore, critical damping should be applied to the weighing scale so the needle can settle as quickly as possible to read from the scale.
Score: 0 pts