B.1 SL/HL Concept 1 of 5

Temperature and Internal Energy

Part of B.1 Thermal Energy Transfers · Unit B — IB Physics 2023

1 Lesson 1 of 5 · B.1 Thermal Energy Transfers
Temperature and Internal Energy
Every substance is a swarm of particles in constant motion. This lesson builds the vocabulary — internal energy, thermal energy, temperature — needed to describe that motion precisely, then connects it to the microscopic equation that defines what temperature actually is.

🥇 Hook – the gold leaf mystery

Imagine you're in Thailand, watching someone place delicate gold leaf onto a Buddha statue. The gold is hammered so thin you could almost see through it. Here's the challenge: if you had just 1 gram of gold, how large a sheet of gold leaf could you make?

Gold leaf being applied to a statue, with a small gold cube and a large thin gold sheet showing the mass-to-area transformation
Fig 1 — Gold leaf is hammered thin enough to see through. A single gram covers an area you wouldn't expect.
💡 Diagnostic question — how can a single gram of gold cover such a large area? What does this tell us about the arrangement of gold atoms? Gold atoms pack together with almost no empty space between them, so a given mass occupies a very small volume — and a small volume, spread thin enough, stretches a long way. We'll calculate exactly how far later in this lesson.

🧩 Internal energy, thermal energy and heat

All substances contain particles with kinetic and potential energy. The total of these is internal energy. Energy transferred from a hotter object to a colder one is thermal energy — also called heat. These are three separate terms and it matters which one you use.

TermDefinition in this courseCommon misconception
Internal energyTotal kinetic + potential energy of ALL particles in a substanceOften confused with "heat"
Thermal energyThe transfer of energy due to a temperature differenceIncorrectly used as "energy inside"
HeatSame as thermal energy (a transfer)Widely misused interchangeably with internal energy
🤔 TOK — does the precision of language in physics eliminate all ambiguity? Why do we have three terms for such similar concepts?

The kinetic theory of matter explains this in terms of particle arrangement. Complete this table for the three states:

PropertySolidLiquidGas
ArrangementRegular patternNo patternNo pattern
Forces between particlesStrong, fixed positionsSome forces overcomeNegligible
SeparationClose togetherStill closeMuch further apart
MotionVibrate in fixed positionsLimited random movementHigh-speed random motion
Particle arrangement diagrams for solid, liquid and gas states
Fig 2 — Solids: a fixed lattice, particles vibrating in place. Liquids: still close, but free to slide past each other. Gases: widely separated, moving randomly.

Gas molecules are spaced roughly 10 molecular diameters apart — about 1000× more than in a liquid or solid. That's why you can walk through air but not through a wall.

Density · SI unit kg m⁻³ $$\rho = \frac{m}{V}$$

Example: 125 g of olive oil has a volume of 137 cm³. Converting, \(m = 0.125\) kg and \(V = 1.37\times10^{-4}\) m³, so \(\rho = 0.125 / (1.37\times10^{-4}) = 912\ \text{kg m}^{-3}\).

🌡️ Temperature scales

The Celsius scale is fixed by the freezing point of water (0°C) and its boiling point (100°C), with 100 equal divisions between them.

The Kelvin scale is absolute: zero kelvin (0 K) is absolute zero, -273.15°C, the coldest temperature physically possible. A change of 1 K equals a change of 1°C.

Celsius ↔ Kelvin $$T(\text{K}) = \theta(°\text{C}) + 273$$
Celsius and Kelvin thermometer scales side by side with matching fill heights
Fig 3 — The two scales share the same size of division; they only differ in where zero is placed.
TaskAnswer
Convert -114°C to K159 K
Convert 933 K to °C660°C
Change from +10°C to -10°C, in K20 K change

⚛️ The microscopic view — the Boltzmann connection

Temperature isn't just a number on a scale — it's a measure of how energetically particles are moving. For an ideal gas, the average random translational kinetic energy per particle is:

Average kinetic energy per particle $$\bar{E}_{\text{k}} = \tfrac{3}{2}k_{\text{B}}T$$

where \(k_{\text{B}} = 1.38\times10^{-23}\ \text{J K}^{-1}\) is the Boltzmann constant and \(T\) is temperature in kelvin.

Two groups of molecules, faster hot molecules on the left and slower cold molecules on the right, with collision arrows transferring energy between them
Fig 4 — Faster (hotter) particles collide with slower (cooler) ones, transferring kinetic energy until the two groups share the same average.
✈️ The moving aircraft problem — a gas cylinder at 20°C is placed on an aircraft flying at 200 m s⁻¹. What happens to the temperature? The ordered motion of the aircraft adds to the ordered kinetic energy of the particles, but the random kinetic energy — the part that determines temperature — is unchanged. The temperature does not increase.

Internal energy is the total random kinetic energy plus the total potential energy of all the particles in a substance. Particles can have three forms of kinetic energy: vibrational (oscillating about a fixed position, dominant in solids), translational (moving from place to place, dominant in liquids and gases), and rotational (molecules spinning). In solids and liquids, electrical forces between particles give significant potential energy; in gases, particles are too far apart for this to matter, so internal energy there is almost entirely kinetic.

$$U = E_{\text{k}} + E_{\text{p}}$$
📜 Nature of Science — before kinetic theory, scientists believed in "caloric fluid", an invisible fluid flowing from hot to cold objects. It couldn't explain why rubbing your hands together generates heat with no fluid flowing anywhere.

📈 Graph mastery – reading temperature graphs

Graph typeAxes (X, Y)ShapeWhat to read
Cooling / warming curvesTime · TemperatureOne curve falls, one rises, both level off and meetThe point where the curves converge is thermal equilibrium — same final temperature, no more net transfer
Average KE vs temperatureTemperature, \(T\) / K · \(\bar{E}_{\text{k}}\) / JStraight line through the originGradient = \(\tfrac32 k_{\text{B}}\); doubling \(T\) doubles \(\bar{E}_{\text{k}}\)
Cooling and warming curves converging to a shared final temperature over time
Fig 5 — A hot object cools, a cold object warms, and both level off at the same final temperature: thermal equilibrium.
Straight line graph of average kinetic energy against temperature through the origin
Fig 6 — \(\bar{E}_{\text{k}}\) is directly proportional to \(T\) in kelvin — never to a Celsius temperature.

✍️ Worked example 1 – the gold leaf problem

Gold has density 19,300 kg m⁻³. What area of foil of thickness \(1.80\times10^{-5}\) cm can be made from 1.0 g of gold?

1
Identify: the volume of gold is fixed; use \(\rho = m/V\) to find it, then divide by the thickness to get area.
2
Data: \(m = 1.0\times10^{-3}\) kg, \(\rho = 19{,}300\ \text{kg m}^{-3}\), thickness \(= 1.80\times10^{-5}\) cm \(= 1.80\times10^{-7}\) m.
3
Equation: \(V = m/\rho = (1.0\times10^{-3})/(19{,}300) = 5.18\times10^{-8}\ \text{m}^3\)
Area \(= V / \text{thickness}\)
4
Answer: Area \(= (5.18\times10^{-8})/(1.80\times10^{-7}) = 0.288\ \text{m}^2\) — nearly the size of a sheet of paper, from just 1 gram of gold.
Diagram showing a small gold cube transformed into a large thin gold sheet with volume, thickness and area labelled
Fig 7 — Same volume, different shape: a 5.18×10⁻⁸ m³ cube of gold flattened to a sheet 1.80×10⁻⁷ m thick covers 0.288 m².

✍️ Worked example 2 – average kinetic energy at room temperature

Calculate the average kinetic energy of gas molecules at room temperature, 20°C.

1
Identify: use \(\bar{E}_{\text{k}} = \tfrac32 k_{\text{B}} T\); temperature must be in kelvin.
2
Data: \(\theta = 20°\text{C}\), so \(T = 20 + 273 = 293\) K. \(k_{\text{B}} = 1.38\times10^{-23}\ \text{J K}^{-1}\).
3
Equation: \(\bar{E}_{\text{k}} = 1.5 \times (1.38\times10^{-23}) \times 293\)
4
Answer: \(\bar{E}_{\text{k}} = 6.1\times10^{-21}\ \text{J}\) per particle.

🌍 Real-world: why ice floats

Water reaches its maximum density at 4°C. Ice is less dense than liquid water — 910 kg m⁻³ compared with 1000 kg m⁻³ — so it floats. This is why lakes freeze from the top down, insulating the water below and letting fish survive winter in liquid water beneath the ice.

✓ Examiner tip: "ice floats because it's frozen" earns nothing. State the actual densities and say ice is less dense than the water it forms in.

🚀 HL extension – the full kinetic theory equation

The equation \(\bar{E}_{\text{k}} = \tfrac32 k_{\text{B}}T\) comes from a more complete kinetic theory result linking pressure, volume and molecular speed:

$$PV = \tfrac{1}{3}Nm\overline{v^2}$$

where \(N\) is the number of particles, \(m\) the mass of one particle, and \(\overline{v^2}\) the mean square speed.
Challenge: if a fixed volume of gas is heated so its temperature doubles (in kelvin), what happens to the pressure, assuming volume and particle number stay fixed? Answer: pressure doubles — \(\bar{E}_{\text{k}} \propto T\) and \(PV \propto Nm\overline{v^2} \propto \bar{E}_{\text{k}}\), so at fixed \(V\) and \(N\), \(P \propto T\).

⚠️ Trap corner – common mistakes

MisconceptionCorrect view
Heat is energy stored inside a hot objectHeat (thermal energy) is energy in transit because of a temperature difference — it is never "contained"
Internal energy and thermal energy mean the same thingInternal energy is the total \(E_{\text{k}}+E_{\text{p}}\) of all particles; thermal energy is specifically the transfer between objects at different temperatures
A faster-moving reference frame makes gas molecules hotterOnly random kinetic energy determines temperature — the aircraft's ordered motion doesn't add to it
Gases have large potential energy between particlesGas particles are far apart, so potential energy is negligible; almost all their internal energy is kinetic
⚠️ Most common slip: describing heat as something an object "has" or "contains". Heat/thermal energy is always a transfer between two objects at different temperatures — say "energy transferred", never "heat contained".
U = Ek + Ep thermal energy = energy in transit T(K) = θ(°C) + 273 Ēk = (3/2)kBT kB = 1.38×10⁻²³ J K⁻¹ ρ = m/V thermal equilibrium: no net transfer conduction · convection · radiation
Practice check — multiple choice
1. Which best describes the difference between thermal energy and internal energy?
A They are identical terms for the same quantity
B Internal energy is the total Ek + Ep of all particles in a substance; thermal energy is the energy transferred due to a temperature difference
C Thermal energy is stored inside a hot object; internal energy is not
D Internal energy only applies to gases
2. 300 K is equivalent to
A 27°C
B 300°C
C -27°C
D 573°C
3. The average translational kinetic energy of a gas particle at 50°C is closest to
A \(6.7\times10^{-21}\) J
B \(4.1\times10^{-21}\) J
C \(1.38\times10^{-23}\) J
D \(3.3\times10^{2}\) J
4. Thermal energy can transfer across a vacuum by
A Conduction
B Convection
C Radiation
D No mechanism transfers energy across a vacuum
5. A sealed gas cylinder at 20°C is placed on an aircraft flying at 200 m s⁻¹. Measured on the aircraft, the gas temperature
A Increases, because molecules gain extra kinetic energy from the plane's motion
B Stays the same — the aircraft's ordered motion doesn't add to the gas's random kinetic energy
C Decreases due to lower air pressure at altitude
D Doubles
Practice check — fill in the blanks

Complete the statements:

Internal energy is the total random kinetic energy plus the total energy of all the particles in a substance. Thermal energy describes the of energy due to a temperature difference. The kelvin scale is related to Celsius by \(T(\text{K}) = \theta(°\text{C}) + \) . The average kinetic energy of a gas particle is given by \(\bar{E}_{\text{k}} = \tfrac32\) \(T\). Particles in a solid have mainly kinetic energy, while particles in a gas have mainly kinetic energy. Two objects in thermal contact reach thermal when there is no net transfer of energy between them.
Exam‑style questions
Exam question · Explain
Q1. Explain the difference between thermal energy and internal energy. [2 marks]
✓ Internal energy is the total kinetic + potential energy of all the particles in a substance.
✓ Thermal energy (heat) is the energy transferred between objects because of a temperature difference — it is not a stored quantity.
Exam question · Calculate
Q2. Convert 300 K to degrees Celsius. [1 mark]
✓ \(\theta = T - 273 = 300 - 273 = 27°\text{C}\).
Exam question · Calculate
Q3. Calculate the average translational kinetic energy of a gas particle at 50°C. [3 marks]
✓ \(T = 50 + 273 = 323\) K.
✓ \(\bar{E}_{\text{k}} = 1.5 \times (1.38\times10^{-23}) \times 323\)
✓ \(\bar{E}_{\text{k}} = 6.7\times10^{-21}\ \text{J}\).
Exam question · State
Q4. State two forms of kinetic energy that particles can have, other than translational. [2 marks]
✓ Vibrational — particles oscillating about a fixed position, dominant in solids.
✓ Rotational — molecules spinning, seen in gases and liquids.
Exam question · Explain
Q5. Explain why thermal energy can be transferred across a vacuum. [2 marks]
✓ Thermal radiation is electromagnetic waves emitted by a surface.
✓ Electromagnetic waves require no medium to travel, so radiation — unlike conduction or convection — works through a vacuum.
Exam question · Show that / Calculate
Q6. A gold ring has a mass of 3.20 g and a volume of \(1.66\times10^{-7}\) m³. The density of gold is 19,300 kg m⁻³. (a) Show that this volume is consistent with the ring being pure gold. (b) The same 3.20 g of gold is instead hammered into a foil of thickness \(2.00\times10^{-7}\) m. Calculate the area of the foil. [4 marks]
✓ (a) \(V = m/\rho = (3.20\times10^{-3})/19{,}300 = 1.66\times10^{-7}\ \text{m}^3\) — matches the given volume.
✓ (b) Same volume, area \(= V/\text{thickness}\)
✓ \(= (1.66\times10^{-7})/(2.00\times10^{-7})\)
✓ \(= 0.829\ \text{m}^2\).
Score: 0 pts